2018년 4월 14일 토요일

양자역학 chapter 7

양자역학 chapter 7
양자역학 chapter 7.hwp


본문
7.17)The pilot of a rocket moving at a velocity 0.8c relative earth observes a second rocket approaching in the opposite direction at a velocity of 0.7c
What does an observer on earth measure for the second rockets velocity?
u prime _ x = u _ x -v over 1-( v over c ^ 2 )u _ x #
```````````= 0.8c-0.7c over 1-( 0.7c TIMES 0.8c over c ^ 2 ) =0.227c
7.19)An observer O is moving along the x-x axis with a speed of c/2 with respect to another observer O. observer O measures a particle moving in the positive y-direction with a speed c over sqrt 3 . Calculate the velocity of the particle as measured by O?
u _ x = u _ x+v over 1+( v over c ^ 2 )u _ x = 0- 1 over 2 c over 1-0 =- 1 over 2 c#
u _ y = u _ y sqrt 1-( v ^ 2 over c ^ 2 ) over 1+( v over c ^ 2 )u _ x = 1 over sqrt 3 TIMES sqrt 1-(0.5) ^ 2 over 1+0 = 1 over 2 c#
u= sqrt u _ x ^ 2 +u _ y ^ 2 = sqrt ( 1 over 2 c) ^ 2 +( 1 over 2 c) ^ 2 = sqrt 2 over 2 c#
tan varphi = u _ y over u _ x = 1 over 2 over - 1 over 2 =-1#
THEREFORE varphi =tan ^ -1 (-1)#
``````````````=-45 ^ DEG `or``135 DEG
7.24)What is the Doppler Shift in 5500뫍 light if the source approaches the observer with velocity of 0.8c?
lambda = lambda _ 0 sqrt 1+( v over c ) over 1-( v over c ) #
5500 ANGSTROM = lambda _ 0 sqrt 1+0.8 over 1-0.8 #
5500 ANGSTROM over sqrt 1+0.8 over 1-0.8 = lambda _ 0 =1833 ANGSTROM #
THEREFORE lambda _ 0 RARROW 1833 ANGSTROM -5500 ANGSTROM =-3667 ANGSTROM

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키워드
역학, 양자역학

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